# Line slope calculator 3x+5y=52

**Straight line given by points A[4; 8] and B[9; 5]**

## Calculation:

**Slope-intercept form of line:**y = -0.6x+10.4

**Canonical form of the line equation:**3x+5y-52 = 0

**Parametric form of the line equation:**

x = 5t+4

y = -3t+8 ; t ∈ R

**Slope:**m = -0.6

**Slope angle of line: φ =**-30°57'50″ = -0.5404 rad

**X intercept:**x

_{0}= 17.3333

**Y intercept:**y

_{0}= q = 10.4

**Distance line from the origin:**d

_{0}= 8.9179

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(5; -3)

**Normal vector: n =**(3; 5)

**Midpoint of the segment AB: M =**[6.5; 6.5]

**Perpendicular Bisector equation:**5x-3y-13 = 0

**Vector OA = (4; 8) ; |OA| = 8.9443**

**Vector OB = (9; 5) ; |OB| = 10.2956**

**Scalar product OA .OB = 76**

**Angle ∠ AOB = 34°22'49″ = 0.6001 rad**